First slide

In YDSE one of the slits is covered with a thin transparent sheet

Question

Interference fringes were produced in Young's double slit experiment using light of wavelength 5000 A. When a film of material 2.5 x 1O-3 cm thick was placed over one of the slits, the fringe pattern shifted by a distance equal to 20 fringe widths. The reactive index of the material of the film is

Easy

A

1.25
B

1.33
C

1.4
D

1.5

Solution

$S = (μ - 1) t (D / 2 d) 2 d i s t a k e n a s d i s \tan c e b e t w e e n t h e s l i t s . But β = \frac{λD}{2 d} or \frac{D}{2 d} = \frac{β}{λ} ∴ S = (μ - 1) t (β / λ) or 20 β = (μ - 1) (2 \cdot 5 \times 10^{- 3}) \{β / (5000 \times 10^{- 8})\} or (μ - 1) = \frac{20 \times 5000 \times 10^{- 8}}{2 .5 \times 10^{- 3}} = 0 .4 or μ = 1 \cdot 4$

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