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Q.

Interference fringes were produced in Young's double slit experiment using light of wavelength 5000 A. When a film of material 2.5 x 1O-3 cm thick was placed over one of the slits, the fringe pattern shifted by a distance equal to 20 fringe widths. The reactive index of the material of the film is

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a

1.25

b

1.33

c

1.4

d

1.5

answer is C.

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Detailed Solution

S=(μ−1)t(D/2d)     2d is taken as distance between the slits.  But β=λD2d  or  D2d=βλ ∴ S=(μ−1)t(β/λ) or 20β=(μ−1)2⋅5×10−3β/5000×10−8 or (μ−1)=20×5000×10−82.5×10−3=0.4 or μ=1⋅4
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