Q.

Interference fringes were produced in Young's double-slit experiment using light of wavelength 5000 Å. When a film of thickness 2.5×10-3 cm was placed in front of one of the slits, the fringe pattern shifted by a distance equal to 20 fringe-width. The refractive index of the material of the film is

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a

1.25

b

1.35

c

1.4

d

1.5

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Shift, Δx=[(μ−1)t]Dd⇒ 20β=(μ−1)tDd⇒ 20λDd=(μ−1)tDd⇒ 20λ=(μ−1)t⇒ μ=20λt+1⇒ μ=20×5000×10−102.5×10−5+1⇒ μ=410+1⇒ μ=1.4

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