Q.
The internal energy change in a system that has absorbed 2 k cals of heat and done 500 J of work is :
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a
7900 J
b
8900 J
c
6400 J
d
5400 J
answer is A.
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Detailed Solution
Q=W+∆U ⇒ W=Q-∆U =2×1000×4.2-500=7900 J
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