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Q.

The internal energy of a gas is given by U = 2pV. It expands from V0 to 2V0 against a constant pressure  ρ0. The heat absorbed by the gas in the process is

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a

2p0V0

b

4p0V0

c

3p0V0

d

p0V0

answer is C.

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Detailed Solution

Heat absorbed,  Q=W+ΔU=p02V0−V0+2p0⋅2V0−2p0V0=p0V0+2p0V0=3p0V0
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