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The internal energy of a gas is given by U = 2pV. It expands from V0 to 2V0 against a constant pressure  ρ0. The heat absorbed by the gas in the process is 

a
2p0V0
b
4p0V0
c
3p0V0
d
p0V0

detailed solution

Correct option is C

Heat absorbed,  Q=W+ΔU=p02V0−V0+2p0⋅2V0−2p0V0=p0V0+2p0V0=3p0V0

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Similar Questions

100 mol of an ideal gas is heated from 10° to 20°C keeping its (i) volume constant (ii) pressure constant.
Let ΔUa and ΔUb denote the change in the internal energy of the gas due to process (i) and (ii),
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