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Internal energy of n_{1} mol of hydrogen at temperature T is equal to the internal energy of n_{2} mol of helium at temperature 2T. The ratio n_{1}/n_{2} is

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a

35

b

23

c

65

d

37

detailed solution

Correct option is C

Internal energy of n moles of an ideal gas at temperature T is given by U=f2nRT (f=degrees of freedom) U1=U2 f1n1T1=f2n2T2∴n1n2=f2T2f1T1=3×25×1=65Here f2 = degrees of freedom of He = 3and, f1 = degrees of freedom of H2 = 5

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