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An inverted u-tube has its two limbs in water and kerosene contained in two beakers. If water rises to a height of $10 c m$ , to what height does kerosene $(density = 0.8 \frac{g m}{c c})$ rise in the other limb ?

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10 cm

12.5 cm

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detailed solution

Correct option is B

h1d1g=h2d2g 10×1=h×0.8 H = 12.5 cm

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An inverted u-tube has its two limbs in water and kerosene contained in two beakers. If water rises to a height of 10 cm , to what height does kerosene (density=0.8gmcc) rise in the other limb ?

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Ready to Test Your Skills?

free study material

An inverted u-tube has its two limbs in water and kerosene contained in two beakers. If water rises to a height of $10 c m$ , to what height does kerosene $(density = 0.8 \frac{g m}{c c})$ rise in the other limb ?