The inward and outward electric flux for a closed surface in units of $$N-m2/C$$ are respectively $$8$$×$$103$$ and $$4$$×$$103$$. Then the total charge inside the surface is [where ε$$0=$$ permittivity constant]

Correct option is 4−4×103ε0 C

Questions

The inward and outward electric flux for a closed surface in units of $N - m^{2} / C$ are respectively $8 \times 10^{3}$ and $4 \times 10^{3} .$ Then the total charge inside the surface is [where $ε_{0} =$ permittivity constant]

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4×103 C

−4×103 C

−4×103ε C

−4×103ε0 C

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detailed solution

Correct option is D

By Gauss’s law ϕ=1ε0Qenclesed Flux entering is -ive and flux leaving is +ive.⇒Qenclosed =ϕε0=−8×103+4×103ε0=−4×103ε0 Coulomb.

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The inward and outward electric flux for a closed surface in units of N-m2/C are respectively 8×103 and 4×103. Then the total charge inside the surface is [where ε0= permittivity constant]

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Ready to Test Your Skills?

free study material

The inward and outward electric flux for a closed surface in units of $N - m^{2} / C$ are respectively $8 \times 10^{3}$ and $4 \times 10^{3} .$ Then the total charge inside the surface is [where $ε_{0} =$ permittivity constant]