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Q.

The inward and outward electric flux for a closed surface in units of N-m2/C are respectively 8×103 and 4×103. Then the total charge inside the surface is [where ε0= permittivity constant]

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a

4×103 C

b

−4×103 C

c

−4×103ε C

d

−4×103ε0 C

answer is D.

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Detailed Solution

By Gauss’s law ϕ=1ε0Qenclesed Flux entering is -ive and flux leaving is +ive.⇒Qenclosed =ϕε0=−8×103+4×103ε0=−4×103ε0 Coulomb.
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