The inward and outward electric flux for a closed surface in units of N-m2/C are respectively 8 × 103 and 4 × 103. Then the total charge inside the surface is (where εo = permittivity constant)
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a
4×103C
b
-4×103C
c
-4×103εoC
d
-4×103εoC
answer is D.
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Detailed Solution
By Gauss's law, ϕ=1εoQenclosed⇒Qenclosed=ϕεo=−8×103+4×103εo=−4×103εoC.