The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between the 3rd and the 4th orbit is
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a
3.40 eV
b
1.51 eV
c
0.85 eV
d
0.66 eV
answer is D.
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Detailed Solution
E3=-13.69=-1.51 eV;E4=-13.616=-0.85 eV ∴E4-E3=0.66 eV