Questions
The ionisation potential of H-atom is 13.6 V. When it is excited from ground state by monochromatic radiations of 970.6 , the number of emission lines will be (according to Bohr's theory)
detailed solution
Correct option is C
1λ=R1n12−1n22⇒1970.6×10−10=1.097×107112−1n22⇒n2=4∴Number of emission lines N=nn−12=4×32=6Talk to our academic expert!
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