An ionization chamber with parallel conducting plates as anode and cathode has 5 × 107 electrons and the same number of singly-charged positive ions per cm3. The electrons are moving at 4 μA/m2. The current density from anode to cathode is The velocity of positive ions moving towards cathode is
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a
0.4 m/s
b
16 m/s
c
zero
d
0.1 m/s
answer is D.
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Detailed Solution
Current density of drifting electrons j = nevn=5 × 107 cm−3=5 × 107 × 106 m−3v=0.4 m−1, e= 1.6 × 10−19 C ⇒ j=3.2 × 10−6 Am−2Current density of ions=4−3.2 × 10−6 = 0.8 × 10−6 Am2This gives v for ions = 0.1 ms−1