Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

An ionization chamber with parallel conducting plates as anode and cathode has 5 × 107 electrons and the same number of singly-charged positive ions per cm3. The electrons are moving at 4 μA/m2. The current density from anode to cathode is  The velocity of positive ions moving towards cathode is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

0.4 m/s

b

16 m/s

c

zero

d

0.1 m/s

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Current density of drifting electrons j = nevn=5 × 107   cm−3=5 × 107 × 106 m−3v=0.4 m−1,  e= 1.6 × 10−19  C ⇒  j=3.2 × 10−6 Am−2Current density of ions=4−3.2  ×  10−6 =  0.8 ×  10−6  Am2This gives v for ions = 0.1  ms−1
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon