Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The ionization energy of a hydrogen-like Bohr atom is 4 Rdybergs. Find the wavelength of radiation emitted when the electron jumps from the first excited state to the ground state:[1Rydberg =2.2×10−18joule][h=6.6×10−34Js,c=3×108m/s.]Bohr radius of hydrogen atom =5×10−11m]

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

400A     °

b

300A     °

c

500A     °

d

600A     °

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The energy in the ground stateE1=−4 RydbergE1=−4×2.2×1018JThe energy of the first excited state (n=2)E2=E14=-2.2×10−18JThe energy differenceΔE=E2−E1=3×2.2×10−18JNow, the wavelength of radiation emitted isλ=hcΔEλ=6.6×10−34×3×1083×2.2×10−18=300A    ∘
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring