First slide

Bohr's atom model

Question

The ionization potential of H atoms is 13.6 V. The energy difference between n = 2 and n = 3 levels is nearest to

Easy

A

1.9 eV
B

2.3 eV
C

3.4 eV
D

4.5 eV

Solution

$△ E = 13.6 (\frac{1}{2^{2}} - \frac{1}{3^{2}}) eV = 1.9 eV$

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