Ionization potential of hydrogen atom is $$13.6$$ eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $$12.1$$ eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be

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Infinity Learn · Accepted Answer

Ionization energy corresponding to ionizationpotential $$=$$ $$-13.6$$ eVPhoton energy incident $$=$$ $$12.1$$ eVSo, the energy of electron in excited $$state=$$ $$-13.6$$ $$+$$ $$12.1$$ $$=$$ $$-1.5$$ eV⇒$$En=$$−$$13.6n2eV$$−$$1.5=$$−$$13.6n2n2=$$−$$13.6$$−$$1.5$$≈$$9$$      ∴$$n=3That$$ is energy of electron in excited state corresponds to third orbit.The possible spectral lies are when electron jumps form orbit $$3rd$$ to $$2nd$$; to $$1st$$ and $$2nd$$ to $$1st$$. Thus, $$3$$ spectral lines are emitted.

Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be

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