First slide

Magnetic field due to a moving charge

Question

Ionized hydrogen atoms and $α$ -particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths $r_{H} : r_{α}$ will be

Easy

A

1 : 4
B

2 : 1
C

1 : 2
D

4 : 1

Solution

$r = \frac{mv}{qB} = \frac{p}{qB} For given p and B, r \propto \frac{1}{q} \Rightarrow \frac{r_{H}}{r_{α}} = \frac{q_{α}}{q_{H}} = \frac{2}{1}$

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