An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of20°C. The temperature at which (both for ball and plate) the ball just passes through the hole is αiron =12×10−6/0C;αbrass =18×10−6/0C
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a
68°C
b
48°C
c
28°C
d
40°C
answer is B.
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Detailed Solution
diron ′=dbrass ′( after heating )diron 1+αiron Δt=dbrass 1+αbrass Δt