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Q.

An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of20°C. The temperature at which (both for ball and plate) the ball just passes through the hole is αiron =12×10−6/0C;αbrass =18×10−6/0C

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a

68°C

b

48°C

c

28°C

d

40°C

answer is B.

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Detailed Solution

diron ′=dbrass ′( after heating )diron 1+αiron Δt=dbrass 1+αbrass Δt
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