Magnetisation and magnetic intensity

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Question

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 $A m^{- 1}$ . The permeability of the material of the rod is $(μ_{0} = 4 π \times 10^{- 7} T m A^{- 1})$

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Solution

$\begin{array}{l} μ = μ_{0} μ_{r} = μ_{0} (x + 1) \\ 4 π \times 10^{- 7} (599 + 1) = 24 π \times 10^{- 5} = 2 .4 π \times 10^{- 4} \end{array}$

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