An iron rod of volume $$10-3$$ $$m3$$ and relative permeability $$1000$$ is placed as core in a solenoid with $$10$$ $$turns/cm$$. If a current of $$0.5$$ A is passed through the solenoid, then the magnetic moment of the rod will be:

Question

An iron rod of volume $$10-3$$ $$m3$$ and relative permeability $$1000$$ is placed as core in a solenoid with $$10$$ $$turns/cm$$. If a current of $$0.5$$ A is passed through the solenoid, then the magnetic moment of the rod will be:

Infinity Learn · Accepted Answer

$$Bnet=Binduced+Bexternal$$⇒μ$$0$$μrH $$=$$ μ$$0I$$ $$+$$μ$$0H$$⇒$$1000$$μ$$0ni=$$μ$$0ni+I$$       here , $$I=intensity$$ of magnetization and H $$=ni$$ $$=Magnetizing$$ field⇒$$I=999ni=999$$×$$1000$$×$$0.5$$ ⇒ magnetic moment of the rod $$=I$$×$$vol=999$$×$$500$$×$$10$$−$$3=9992=499.5$$≈$$5$$×$$102Am2$$

An iron rod of volume $10^{- 3} m^{3}$ and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be:

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An iron rod of volume 10-3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be:

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An iron rod of volume $10^{- 3} m^{3}$ and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be: