In an isolated charged parallel plate capacitor the electrostatic potential energy stored in it is 12µJ. Find the work done in increasing the separation between the plates to 2 times its original value.
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a
6µJ
b
18µJ
c
8µJ
d
12µJ
answer is D.
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Detailed Solution
Ci=ε0Ad and Cf=ε0A2d=Ci2∴Ui=Q22Ci and Uf=Q22Cf=Q22Ci2=2Ui∴W=Uf−Ui=2Ui−Ui=Ui=12μJ