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In an isosceles triangle of side _{$6 \sqrt{2}$} cms, the length of the base for which the area is maximum is

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Correct option is B

x2=(62)2+(62)2 =72+72=144 x=12

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In an isosceles triangle of side 62 cms, the length of the base for which the area is maximum is

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In an isosceles triangle of side _{$6 \sqrt{2}$} cms, the length of the base for which the area is maximum is