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For an isothermal expansion of a perfect gas, the value of $\frac{ΔP}{P}$ is equal

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−γ1/2ΔVV

−ΔVV

−γΔVV

−γ2ΔVV

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detailed solution

Correct option is B

Differentiate PV=constant w.r.t V⇒PΔV+VΔP=0⇒ΔPP=−ΔVV

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For an isothermal expansion of a perfect gas, the value of ΔPP is equal

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For an isothermal expansion of a perfect gas, the value of $\frac{ΔP}{P}$ is equal