Q.

In an isothermal expansion at temperature T, the work done in expanding a gas from volume 2V to 5V is W. The work done in expanding the same gas from 10V to 25V at same temperature  2T will be

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a

5 w

b

10 W

c

4 w

d

2 W

answer is D.

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Detailed Solution

work done in isothermal process is nRT lnV2V1    here in  first case V2V1=52   for the  second case V2V1= 2510=52  but work done is proportional to T  as temperature is doubled work done is also doubled
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