First slide
Different type of processes
Question

In an isothermal expansion at temperature T, the work done in expanding a gas from volume 2V to 5V is W. The work done in expanding the same gas from 10V to 25V at same temperature  2T will be

Moderate
Solution

work done in isothermal process is nRT lnV2V1    here in  first case V2V1=52   for the  second case V2V1= 2510=52  but work done is proportional to T  as temperature is doubled work done is also doubled 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App