Q.
In an isothermal expansion at temperature T, the work done in expanding a gas from volume 2V to 5V is W. The work done in expanding the same gas from 10V to 25V at same temperature 2T will be
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a
5 w
b
10 W
c
4 w
d
2 W
answer is D.
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Detailed Solution
work done in isothermal process is nRT lnV2V1 here in first case V2V1=52 for the second case V2V1= 2510=52 but work done is proportional to T as temperature is doubled work done is also doubled
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