First slide

Thermodynamic processes

Question

In an isothermal process the volume of an ideal gas is halved. One can say that

Easy

A

Work done by the gas is positive
B

Internal energy of the system increases
C

Work done by the gas is negative
D

Internal energy of the system decreases.

Solution

Internal energy of the system decreases.
$d U = 0 and work done = d W = P (V_{2} - V_{1})$
$\begin{array}{l} ∵ V_{2} = \frac{V_{1}}{2} = \frac{V}{2} \\ d W = - \frac{P V}{2} \end{array}$

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