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Q.

It is required to prepare a steel metre scale such that the millimetre intervals are to be accurate within 0.0005 mm at a certain temperature. Maximum temperature variationallowable during the rulings of millimetre marks is :(αsteel=13.22×10-6/C  o)

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a

37.8°C

b

45.4°C

c

10.2°C

d

62.6°C

answer is A.

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Detailed Solution

Here,l=1 mm,∆l=0.0005 mm As,                   ∆l=l α ∆T So,                   ∆T=∆lαl=0.000513.22×10-6×1=37.8C  o.
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