First slide
Thermal expansion
Question

It is required to prepare a steel metre scale such that the millimetre intervals are to be accurate within 0.0005 mm at a certain temperature. Maximum temperature variation
allowable during the rulings of millimetre marks is :
(αsteel=13.22×10-6/C  o)

Easy
Solution

Here,l=1 mm,l=0.0005 mm As,                   l=l α T So,                   T=lαl=0.000513.22×10-6×1=37.8C  o.

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