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Q.

It takes 10 minutes to cool a liquid from 610C to 590C. If room temperature is 300C then find the time taken in coolking from 510C to 490C

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a

15 min

b

12 min

c

18 min

d

20 min

answer is A.

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Detailed Solution

In first case 61-5910 = K[61+592-30] ------(i)In second case 51-49t = K[51+492-30]-----(ii)By solving t = 15 min.
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