First slide

Specific heat

Question

420 joule of energy supplied to 10 g of water will raise its temperature by nearly:

Moderate

A

1 C^o
B

4.7 C⁰
C

10 C⁰
D

42 C⁰

Solution

$Q = ms ∆ θ \Rightarrow ∆ θ = \frac{420}{(10 \times 10^{- 3}) (4200)} = 10 C^{o}$

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