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Questions  

A junction diode has a resistance of 25Ω when forward biased and 2500Ω when reverse biased. then the current through the diode shown in the figure is 

a
4/2510 A
b
6/2510 A
c
4/35 A
d
6/35 A

detailed solution

Correct option is C

The diode is forward biased, So i=−2−)−625+10A=435A

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