A junction diode has a resistance of 25Ω when forward biased and 2500Ω when reverse biased. then the current through the diode shown in the figure is

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4/2510 A

6/2510 A

4/35 A

6/35 A

answer is C.

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Detailed Solution

The diode is forward biased, So i=−2−)−625+10A=435A

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