First slide

P-N junction diode

Question

A junction diode has a resistance of $25 Ω$ when forward biased and $2500 Ω$ when reverse biased. then the current through the diode shown in the figure is

Easy

A

4/2510 A
B

6/2510 A
C

4/35 A
D

6/35 A

Solution

The diode is forward biased, So $i = \frac{(- 2) -) - (6)}{25 + 10} A = \frac{4}{35} A$

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