First slide

Diodes

Question

For a junction diode, the ratio of forward current ( $I_{f}$ ) and reverse current ( $I_{r}$ ) is

Difficult

A

$e^{- \frac{V}{K T}}$
B

$e^{\frac{V}{K T}}$
C

$e^{\frac{e V}{K T}} + 1$
D

$e^{\frac{e V}{K T}} - 1$

Solution

$R e l a t i o n b e t w e e n f o r w a r d c u r r e n t a n d r e v e r s e c u r r e n t I_{f} = I_{r} (e^{\frac{e V}{K T}} - 1) \Rightarrow \frac{I_{f}}{I_{r}} = e^{\frac{e V}{K T}} - 1$

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