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Q.

K is the force constant of a spring. The work done in increasing its extension from l1 to l2 will be

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a

Kl2−l1

b

K2l2+l1

c

Kl22−l12

d

K2l22−l12

answer is D.

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Detailed Solution

extension l1, the stored energy =12KI12At extension I2, the stored energy =12Kl22Work done in increasing its extension from l1 to I2=12Kl22−l12
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