First slide

Elastic Modulie

Question

K is the force constant of a spring. The work done in increasing its extension from $l_{1} to l_{2}$ will be

Easy

A

$K (l_{2} - l_{1})$
B

$\frac{K}{2} (l_{2} + l_{1})$
C

$K (l_{2}^{2} - l_{1}^{2})$
D

$\frac{K}{2} (l_{2}^{2} - l_{1}^{2})$

Solution

At extension $l_{1}$ , the stored energy = $\frac{1}{2} {Kl}_{1}^{2}$
At extension $l_{2}$ , the stored energy = $\frac{1}{2} {Kl}_{2}^{2}$
Work done in increasing its extension from $l_{1} to l_{2}$
= $\frac{1}{2} K (l_{2}^{2} - l_{1}^{2})$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App