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Questions  

K1 and K2 are the maximum kinetic energies of the photo electrons emitted when light of wave lengths λ1 and λ2 respectively are incident on a metallic surface. If {\lambda _1} = 3{\lambda _2}\ then

a
b
c
K1 > 3K2
d
K2 = 3K1

detailed solution

Correct option is B

K2 = 3[K1 + Wo] – Wo ;K2 = 3K1 + 2Wo

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