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Kα wavelength emitted by an atom of atomic number Z = 11 is λ. The atomic number for an atom that emits Kα radiation with wavelength 4λ is

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a
Z=6
b
Z=4
c
Z=11
d
Z=44

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detailed solution

Correct option is A

f1=vλ1=a(11−1) and f2=vλ2=a(Z−1) By dividing, λ2λ1=10Z−1 ⇒41=10Z−1 ⇒Z=6


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