Kalpit and Mukesh are playing with two different balls of masses m and $$2m$$ respectively. If Kalpit throws his ball vertically up and Mukesh at an angle θ,such that time of flight of both balls is same . The height attained by the two balls are in the ratio of :

Question

Kalpit and Mukesh are playing with two different balls of masses m and $$2m$$ respectively. If Kalpit throws his ball vertically up and Mukesh at an angle θ,such that time of flight of both balls is same . The height attained by the two balls are in the ratio of :

Infinity Learn · Accepted Answer

Let $$u1$$ and $$u2$$ be the initial velocities respectively. If $$h1$$ and $$h2$$ are theheights attained by them, $$thenh1$$ $$=u122g$$  and   $$h2$$ $$=u22sin2$$θ$$2g$$                        ..$$.1The$$ times of ascent of balls are equal, we have $$tt=u1/g$$ $$=u2$$ $$sin$$ θ$$/g$$∴$$u1$$ $$=$$ $$u2$$ $$sin$$θ                                                  ... $$2divide$$ the heights of equation (1)From$$ eq.  $$1$$  $$h1h2=u12u22sin2$$θ                       ... $$3substitute$$ $$equation(2) in (3) $$h1h2=11$$

Kalpit and Mukesh are playing with two different balls of masses m and 2m respectively. If Kalpit throws his ball vertically up and Mukesh at an angle $θ$ ,such that time of flight of both balls is same . The height attained by the two balls are in the ratio of :

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Kalpit and Mukesh are playing with two different balls of masses m and 2m respectively. If Kalpit throws his ball vertically up and Mukesh at an angle θ,such that time of flight of both balls is same . The height attained by the two balls are in the ratio of :

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Kalpit and Mukesh are playing with two different balls of masses m and 2m respectively. If Kalpit throws his ball vertically up and Mukesh at an angle $θ$ ,such that time of flight of both balls is same . The height attained by the two balls are in the ratio of :