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The K.E of photo electron ejected from a metal surface by light of wave length 3100A0   range from 0 to 2.4x1019 J the stopping potential will be equal to

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a
1.5V
b
15V
c
1.1V
d
1.15V

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detailed solution

Correct option is A

k.Emx=eVs ,2.4X10−191.6X10−19eV,     Vs=1.5V,


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