The K.E. of photo electron ejected from a metal surface by light of wave length 2000 A0 range from zero to 3.2 x 10-19J . The stopping potential will be equal to

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3.2V

6.4V

1.6V

answer is A.

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Detailed Solution

ev0=kemax=3.2×10−19J V0=3.2×10¯191.6×10−19=2V

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