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Questions  

The K.E. of photo electron ejected from a metal surface by light of wave length  2000A0 range from zero to 3.2 x 10-19J .  The stopping potential will be equal to

a
2V
b
3.2V
c
6.4V
d
1.6V

detailed solution

Correct option is A

ev0=kemax=3.2×10−19J V0=3.2×10¯191.6×10−19=2V

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