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Q.

Keeping the velocity of projection constant, the angle of projection is increased from 0° to 90º. Then the maximum height of the projectile

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a

goes on increasing up to 900

b

decreases up to 900

c

increase up to 450 and decreases beyond it

d

decreases up to 450 and increases beyond it

answer is A.

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Detailed Solution

Hmax = u2sin2α / 2gAt α = 00 , Hmax = 0 and α = 900 , Hmax has the maximum value of u2/2g , So option (1) is right.
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