Keeping the velocity of projection constant, the angle of projection is increased from 00 to 900. Then the horizontal range of the projectile
goes on increasing up to 900
decreases up to 900
increases up to 450 and decreases afterwards
decreases up to 450 and increases afterwards
R=u2sin2αg
'R' is maximum at α = 450
'R' is zero at α = 00 and α =900
so option - (3) is correct