2kg of air is heated at a constant volume. The temperature of air is increased from 293K to 313K. If the specific heat of air at constant volume is 0.718 kJ/kg-k, the amount of heat absorbed in kJ and kcal is, (J = 4.2kcal)

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6.838 kj

7.8kj

14.68kj

28.72kj

answer is D.

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Detailed Solution

At constant volume w = 0ΔQ=ΔU=nCvΔT=mcvΔTΔQ=2×0.718×103×313-293=28.72kJ

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