First slide

Thermodynamic processes

Question

2kg of air is heated at a constant volume. The temperature of air is increased from 293K to 313K. If the specific heat of air at constant volume is 0.718 kJ/kg-k, the amount of heat absorbed in kJ and kcal is, (J = 4.2kcal)

Moderate

A

6.838 kj
B

7.8kj
C

14.68kj
D

28.72kj

Solution

At constant volume w = 0
$\begin{array}{l} Δ Q = Δ U = n C_{v} Δ T = m c_{v} Δ T \\ Δ Q = 2 \times 0.718 \times 10^{3} \times (313 - 293) = 28.72 k J \end{array}$

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