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A 4kg ball moving at 48ms1 undergoes inelastic head-on collision with an 8kg ball moving in the opposite direction at 96ms1. If the coefficient of restitution is 23, their velocities in ms1 after impact are

a
–56, –8
b
−16, –112
c
–14, –2
d
–7, –1

detailed solution

Correct option is B

4×48−8×96=4×v1+8v2 192−768=4v1+8v2 4v1+8v2=−576 -----(1)23=v2−v1u1+u2⇒23=v2−v148+96 v2−v1=23×144=96 -----(2)Solving (1) and (2)v1+2v2=−144 −v1+v2=96 3v2=−48 v2=−16m/s  v1=−112m/s

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