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Q.

A 4kg ball moving at 48 ms−1 undergoes inelastic head-on collision with an 8kg ball moving in the opposite direction at 96 ms−1. If the coefficient of restitution is 23, their velocities in ms−1 after impact are

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a

–56, –8

b

−16, –112

c

–14, –2

d

–7, –1

answer is B.

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Detailed Solution

4×48−8×96=4×v1+8v2 192−768=4v1+8v2 4v1+8v2=−576 -----(1)23=v2−v1u1+u2⇒23=v2−v148+96 v2−v1=23×144=96 -----(2)Solving (1) and (2)v1+2v2=−144 −v1+v2=96 3v2=−48 v2=−16m/s  v1=−112m/s
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