A 0.5 kg ball moving with a speed of 12 m/sec strikes a hard wall at an angle of 300 with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 s, the average force acting on the wall is

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96 N

48 N

24 N

12 N

answer is C.

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Detailed Solution

F=2mvsin θt=2×0.5×12×sin 30∘0.25=48×12=24N

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