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A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0m. How much energy is dissipated by air drag acting on the ball during the ascent (in J) (take g=9.8 m/s2)

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answer is 9.8.

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Detailed Solution

If there is no air drag then maximum height H=u22g=14×142×9.8=10 mBut due to air drag ball reaches up to height 8m only. So loss in energy=mg(10−8)=0.5×9.8×2=9.8 J

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A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0m. How much energy is dissipated by air drag acting on the ball during the ascent (in J) (take g=9.8 m/s2)