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Question

A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0m. How much energy is dissipated by air drag acting on the ball during the ascent (in J) (take g=9.8 m/s²)

Moderate

Solution

If there is no air drag then maximum height
$H = \frac{u^{2}}{2 g} = \frac{14 \times 14}{2 \times 9 .8} = 10 m$
But due to air drag ball reaches up to height 8m only. So loss in energy
$= mg (10 - 8) = 0 .5 \times 9 .8 \times 2 = 9 .8 J$

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