First slide

Work

Question

A 4kg block is acted upon by force as shown in figure. The work done by the force from x=0 to x=8m is

Moderate

A

1.25J
B

1.25mJ
C

-1.25J
D

-1.25mJ

Solution

Work done=Area of F-x graph
$\begin{array}{l} W = (500 \times 10^{- 3} \times 2) + (\frac{1}{2} \times 500 \times 10^{- 3} \times 2) + 0 + \frac{1}{2} \times (- 250 \times 10^{- 3}) \\ W = 1 + 0.5 - 0.25 = 1.25 J \end{array}$

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