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Questions  

A 4kg block is acted upon by force as shown in figure. The work done by the force from x=0  to x=8m  is

a
1.25J
b
1.25mJ
c
-1.25J
d
-1.25mJ

detailed solution

Correct option is A

Work done=Area of F-x graphW=(500×10−3×2)+(12×500×10−3×2)+0+12×(−250×2×10−3)W=1+0.5−0.25=1.25J

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