First slide

Static friction

Question

A 4 kg block is in equilibrium on a rough inclined surface having inclination of $30^{o}$ with horizontal. Then frictional force acting on the block is

Easy

A

20 N
B

30 N
C

$20 \sqrt{3}$ N
D

$10 \sqrt{3}$ N

Solution

Net force along the inclined force must be zero.
$∴ f - m g \sin θ = 0$
$\Rightarrow f = 4 \times 10 \times \sin 30^{o} N = 20 N$

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