A 15 kg block is initially moving along a smooth horizontal surface with a speed of v = 4 m/s to the left. It is acted by a force F, which varies in the manner shown. Determine the velocity of the block at t = 15 seconds.Given that, F = 40 cos (π10)t.

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12.5 m/s

8.5 m/s

20 m/s

9.5 m/s

answer is A.

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Detailed Solution

Change in linear momentum ∆P = ∫F dt15(vf+u) = ∫01540 cos(π10)t dtvf =- 4+4015[sin(π10)tπ10]150 m/s=-4 + 40015π(-1) = -12.5 m/s

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