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Questions  

A 15 kg block is initially moving along a smooth horizontal surface with a speed of v = 4 m/s to the left. It is acted by a force F, which varies in the manner shown. Determine the velocity of the block at t = 15 seconds.

Given that, F = 40 cos (π10)t.

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a
12.5 m/s
b
8.5 m/s
c
20 m/s
d
9.5 m/s

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detailed solution

Correct option is A

Change in linear momentum ∆P = ∫F dt15(vf+u) = ∫01540 cos(π10)t dtvf =- 4+4015[sin(π10)tπ10]150 m/s=-4 + 40015π(-1) = -12.5 m/s

ctaimg

Similar Questions

Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.

Statement II : The equality of mg and R has no connection with the third law.

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