A 15 kg block is initially moving along a smooth horizontal surface with a speed of v = 4 m/s to the left. It is acted by a force F, which varies in the manner shown. Determine the velocity of the block at t=15 seconds. Given that, F=40cos⁡π10t

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12.5 m/s

8.5 m/s

20 m/s

9.5 m/s

answer is A.

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Detailed Solution

Change in linear momentum ΔP=∫Fdt15vf+u=∫015 40cos⁡π10tdtvf=−4+4015sin⁡(π/10)tπ/10015=−4+40015π(−1)=−12.5m/s

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