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A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is (g=10ms2)

a
2 ms−2, 2 ms−2
b
2 ms−2, 1 ms−2
c
3 ms−2, 1 ms−2
d
4 ms−2, 1 ms−2

detailed solution

Correct option is A

as acceleration of the system is  causing a force on upper block less than limiting friction on upper block Since    The blocks move together with same  acceleration.   a=FM1+M2=122 +4=2 ms-2

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Similar Questions

A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is ______ N. (Round off to the Nearest integer)
(Take  g=10ms2)


 


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