A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is (g=10ms−2)
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a
2 ms−2, 2 ms−2
b
2 ms−2, 1 ms−2
c
3 ms−2, 1 ms−2
d
4 ms−2, 1 ms−2
answer is A.
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Detailed Solution
as acceleration of the system is causing a force on upper block less than limiting friction on upper block Since The blocks move together with same acceleration. a=FM1+M2=122 +4=2 ms-2