Q.

A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is (g=10ms−2)

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a

2 ms−2, 2 ms−2

b

2 ms−2, 1 ms−2

c

3 ms−2, 1 ms−2

d

4 ms−2, 1 ms−2

answer is A.

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Detailed Solution

as acceleration of the system is  causing a force on upper block less than limiting friction on upper block Since    The blocks move together with same  acceleration.   a=FM1+M2=122 +4=2 ms-2
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