Questions
A 4 kg block A is placed at the top of 8 kg block B which rests on a smooth table. A just slips on B when a force of 20 N is applied on A. The maximum horizontal force F required to make both A & B move together is
detailed solution
Correct option is C
Fmax=μs⋅mg1+MmWhere M = Mass of the block on which force F is applied. and m = Mass of the upper block.20=μs×4×10×1+48⇒μs=1/3∴Fmax=13×4×10×1+84N⇒N=40NTalk to our academic expert!
Similar Questions
A block A of mass 3kg and another block B of mass 2 kg are connected by a light inextensible string as shown in figure. If the coefficient of friction between the surface of the table and A is 0.5. What minimum mass C should be placed on A so that the system is in equilibrium? ()
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