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The 3 kg block is projected along the frictionless surface with a velocity of 2 m/s as shown in figure. What will be the velocity of 3 kg block when 6 kg block will be moving with same velocity as the centre of mass of the blocks. 

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By Expert Faculty of Sri Chaitanya
a
14m/s
b
34m/s
c
23m/s
d
13m/s

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detailed solution

Correct option is C

VC=velocity of centre of mass =3×26+3m/s=23m/s∴ 6×23+3×V=(6+3)×VC⇒V=13[9×23−6×23]ms=23 ms


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